Abrowser won't run Regexr
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I'm having issues running Regexr in Abrowser.
http://bluehome.net/csh/screenshot/2017/11/24/regexr
What could be going wrong?
Regexr is a free software web app for interactively exploring regular
expressions.
--
Caleb Herbert
OpenPGP public key: http://bluehome.net/csh/pubkey
Probably an incompatibility with one of your add-ons (try to disable them half by half to find the culprit). It works here.
That's the first thing I did. It still didn't work.
1. Make a test folder/directory with various dummy files that would be
similar to the RegEx (if you are making directory/path expansion
tests). Or a test file with contents inside (if you are testing for
file's contents).
2. Make the RegEx software attempt the wanted RegEx against that
directory or file.
See the results.
Done, no need to run any "RegExr". ;)
Alternatively, go to the support channels of the programming language
you are writting on and ask there for a revision on the matter, or you
can also ask us here. ;)
2017-11-24T14:48:22-0600 Caleb Herbert wrote:
> I'm having issues running Regexr in Abrowser.
>
> http://bluehome.net/csh/screenshot/2017/11/24/regexr
>
> What could be going wrong?
>
> Regexr is a free software web app for interactively exploring regular
> expressions.
--
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GIMP, Inkscape SVG, JPG, LibreOffice (padrão ODF), OGG, OPUS, PDF
(apenas sem DRM), PNG, TXT, WEBM.
If I were going that route, I'd be using regex-builder in Emacs, but
sometimes even it isn't interactive enough.
I don't understand how interactive it's supposed to be?
Do you mean that it should ask you everytime "do you want to match
file?".
I don't which RegEx engine you want to use, nor the programming
language, but at least in GNU `find', one can use something like:
find "." -regex '.*\.png$' -print
... this will search recursively from the current directory (!) and
print the relative path to each matched file that has .png file
extension (although this doesn't guarantee that the MIME type will be
that of .png file). This provides some "interactive result" because it
does nothing besides printing the matches.
Note that GNU `find' uses Emacs regular expressions by default (unless
you use `-regextype' before), which as far as I know is similar to Basic
Regular Expressions but with more features.
Finally, notice that your `-regex' must deal with the full relative path,
that is, simply using "\.png$" would return nothing (because it fails to
consider "." path, and also the subdirectories).
You could elaborate a little more and say that you only want things
inside two directory/path levels, like so:
find "." -regex '\([^/]+/\)\([^/]+/\)[^/]+\.png$' -print
But this is probably not efficient, it would be best to use:
find "." -mindepth 2 -maxdepth 2 -name '*.png' -print
Note that in the last command example `-name' uses Pathname Expansion
(see `info bash' for explanation), not regular expressions.
2017-11-27T08:43:50-0600 Caleb Herbert wrote:
> If I were going that route, I'd be using regex-builder in Emacs, but
> sometimes even it isn't interactive enough.
>
>
--
- https://libreplanet.org/wiki/User:Adfeno
- Palestrante e consultor sobre /software/ livre (não confundir com
gratis).
- "WhatsApp"? Ele não é livre. Por favor, veja formas de se comunicar
instantaneamente comigo no endereço abaixo.
- Contato: https://libreplanet.org/wiki/User:Adfeno#vCard
- Arquivos comuns aceitos (apenas sem DRM): Corel Draw, Microsoft
Office, MP3, MP4, WMA, WMV.
- Arquivos comuns aceitos e enviados: CSV, GNU Dia, GNU Emacs Org, GNU
GIMP, Inkscape SVG, JPG, LibreOffice (padrão ODF), OGG, OPUS, PDF
(apenas sem DRM), PNG, TXT, WEBM.
I'm using Regexr because I want something like Daring Fireball's
Markdown Web Dingus, but for regular expressions.
That was exactly my suggestion, with the advantage that you don't need
internet. ;)
2017-11-27T10:59:53-0600 Caleb Herbert wrote:
> I'm using Regexr because I want something like Daring Fireball's
> Markdown Web Dingus, but for regular expressions.
>
> https://daringfireball.net/projects/markdown/dingus
>
>
Does it have a regex key on the side or elsewhere?
Unfortunatelly no, but you can test with various dummy files/texts.
I wonder however, what exactly you want the regular expression to match,
or not to match, and which programming language is it?
2017-11-27T11:56:02-0600 Caleb Herbert wrote:
> Does it have a regex key on the side or elsewhere?
>
>
The '$' (end) of any line that matches '^x '.
I assume that by "the end" of the line you want to actually capture the
last character, which ever it is.
Suppose you have a text file like this (the underlines are *also*
spaces, please correct them):
--8<---------------cut here---------------start------------->8---
c ^x a1
y b2
z c3
b x d4
y e5
z f6
x abC W-
a ^x_
y_
z_
e ^x
x_
d qwerty ^x azerty aBc
--8<---------------cut here---------------end--------------->8---
Then, assuming you want to match a literal "^x " and are using Basic
Regular Expressions in GNU `sed', a command such as this:
--8<---------------cut here---------------start------------->8---
sed -n 's/^.*\^x .*\(.\)$/\1/gp' "file.txt"
--8<---------------cut here---------------end--------------->8---
Would print:
--8<---------------cut here---------------start------------->8---
1
c
--8<---------------cut here---------------end--------------->8---
If you instead want "^" to be considered as special in "^x ", this:
--8<---------------cut here---------------start------------->8---
sed -n 's/^x .*\(.\)$/\1/gp' "file.txt"
--8<---------------cut here---------------end--------------->8---
Would display this:
--8<---------------cut here---------------start------------->8---
-
--8<---------------cut here---------------end--------------->8---
The `-n' option in `sed' tells it to print only when asked to, the
`s/regex/subst/flags' looks for a match of regular expression and
replaces it, the "g" flag makes it replace all matches, and "p" prints
the line if a match was found.
Notice however that the captures made so far (of the last character)
don't overlap with the controlling match ("^x "), that is, so far a
string such as "x " wouldn't have the space captured. As far as my
limited knowledge goes, in cases where you have to do a second match
based on the existance of another match, it's more readable to use *two*
regular expressions (there are some regular expression standards that
allow this nesting at the expense of human readability, but I'm still
not that good on these ones).
The commands bellow use *two* regular expressions, for literal "^x " and
for the special "^" in "^x ", respectively:
--8<---------------cut here---------------start------------->8---
sed -n '/\^x / { s/^.*\(.\)$/\1/gp }' "file.txt"
sed -n '/^x / { s/^.*\(.\)$/\1/gp }' "file.txt"
--8<---------------cut here---------------end--------------->8---
Unless an address is given, `sed' applies commands to all lines. The
/regex/ is an address type that selects lines matching a regular
expression. After the address comes a command, the "{" and "}" are there
for readability (but are very important if you would want to apply more
commands to the same address).
Yet again I must remind you that some programming languages have
different regular expression standards, and so far I don't know which
one you want.
Finally, if you want to capture the line feed literally, then this can
be more tricky. Personally, I would test how the file's first line ends
and apply the same for the future lines I want to write.
I hope this helps. ;)
2017-11-27T15:01:09-0600 Caleb Herbert wrote:
> The '$' (end) of any line that matches '^x '.
>
>
In the last paragraph, by "line terminator", I meant either:
- line feed only (LF, 0x0A, "\n"). Default for Unix-compliant operating
systems such as GNU;
- carriage return only (CR, 0x0D, "\r"). Default for Mac;
- carriage return and line feed (CRLF, 0x0D, "\r\n"). Default for
Windows.
Most commands assume that you are dealing with LF only, so the special
"$" in regular expressions already mean only "\n". There are other tools
such as `tr' which can do translations (replacements from one terminator
to other) and also `awk' for which by modifying some Awk variables you
can change how it considers input records as terminated (noting that
"records" for Awk can be considered as lines by default).
2017-11-27T21:34:33-0200 Adonay Felipe Nogueira wrote:
> I assume that by "the end" of the line you want to actually capture the
> last character, which ever it is.
>
> Suppose you have a text file like this (the underlines are *also*
> spaces, please correct them):
>
> --8<---------------cut here---------------start------------->8---
> c ^x a1
> y b2
> z c3
> b x d4
> y e5
> z f6
> x abC W-
> a ^x_
> y_
> z_
> e ^x
> x_
> d qwerty ^x azerty aBc
> --8<---------------cut here---------------end--------------->8---
>
>
> Then, assuming you want to match a literal "^x " and are using Basic
> Regular Expressions in GNU `sed', a command such as this:
>
> --8<---------------cut here---------------start------------->8---
> sed -n 's/^.*\^x .*\(.\)$/\1/gp' "file.txt"
> --8<---------------cut here---------------end--------------->8---
>
>
> Would print:
>
> --8<---------------cut here---------------start------------->8---
> 1
> c
> --8<---------------cut here---------------end--------------->8---
>
>
> If you instead want "^" to be considered as special in "^x ", this:
>
> --8<---------------cut here---------------start------------->8---
> sed -n 's/^x .*\(.\)$/\1/gp' "file.txt"
> --8<---------------cut here---------------end--------------->8---
>
>
> Would display this:
>
> --8<---------------cut here---------------start------------->8---
> -
> --8<---------------cut here---------------end--------------->8---
>
>
> The `-n' option in `sed' tells it to print only when asked to, the
> `s/regex/subst/flags' looks for a match of regular expression and
> replaces it, the "g" flag makes it replace all matches, and "p" prints
> the line if a match was found.
>
> Notice however that the captures made so far (of the last character)
> don't overlap with the controlling match ("^x "), that is, so far a
> string such as "x " wouldn't have the space captured. As far as my
> limited knowledge goes, in cases where you have to do a second match
> based on the existance of another match, it's more readable to use *two*
> regular expressions (there are some regular expression standards that
> allow this nesting at the expense of human readability, but I'm still
> not that good on these ones).
>
> The commands bellow use *two* regular expressions, for literal "^x " and
> for the special "^" in "^x ", respectively:
>
> --8<---------------cut here---------------start------------->8---
> sed -n '/\^x / { s/^.*\(.\)$/\1/gp }' "file.txt"
> sed -n '/^x / { s/^.*\(.\)$/\1/gp }' "file.txt"
> --8<---------------cut here---------------end--------------->8---
>
> Unless an address is given, `sed' applies commands to all lines. The
> /regex/ is an address type that selects lines matching a regular
> expression. After the address comes a command, the "{" and "}" are there
> for readability (but are very important if you would want to apply more
> commands to the same address).
>
> Yet again I must remind you that some programming languages have
> different regular expression standards, and so far I don't know which
> one you want.
>
> Finally, if you want to capture the line feed literally, then this can
> be more tricky. Personally, I would test how the file's first line ends
> and apply the same for the future lines I want to write.
>
> I hope this helps. ;)
> If you instead want "^" to be considered as special in "^x ", this:
>
> --8<---------------cut here---------------start------------->8---
> sed -n 's/^x .*\(.\)$/\1/gp' "file.txt"
> --8<---------------cut here---------------end--------------->8---
Your suggestion does not add to the lines. It deletes them entirely.
cal@leela:~$ sed 's/^x .*\(.\)$/CHARIZARD/gp' "file.txt"
c ^x a1
y b2
z c3
b x d4
y e5
z f6
CHARIZARD
CHARIZARD
a ^x
y
z
e ^x
x
d qwerty ^x azerty aBc
Also, it matches incorrectly.
* An extra CHARIZARD line was inserted
* "x " at the beginning of the penultimate line was NOT matched
My intended result is to ADD text to the end of any lines that start
with "x ".
c ^x a1
y b2
z c3
b x d4
y e5
z f6
x abC W-CHARIZARD
a ^x
y
z
e ^x
x CHARIZARD
d qwerty ^x azerty aBc
Substitute the end of the line with "text" (i.e., concatenate "text" to the line) if the line starts with "x" (and keep the remaining lines unaltered):
$ sed '/^x/ s/$/text/'
# or
$ awk '/^x/ { $0 = $0 "text" } { print }'
If, as above, no file (including pipes) is given to the command, the input is read from the keyboard: you type a line of text and, right after typing [Enter], you get the respective line processed. Indeed, most text-processing commands work line by line. The command is "interactive" in that sense. However, it is usually a better idea to list all problematic cases in a file to not have to retype the same input every time you fix/refine your command line.
That's perfect! Thanks!
Well, in this case, the suggestions given by Magic Banana work well
together with mine. ;)
The extra line that you said gets inserted is because you forgot `-n',
if you absolutely don't want `-n', then remove the `p' flag from the `s'
command.
2017-11-27T18:18:36-0600 Caleb Herbert wrote:
> Your suggestion does not add to the lines. It deletes them entirely.
>
>
> cal@leela:~$ sed 's/^x .*\(.\)$/CHARIZARD/gp' "file.txt"
> c ^x a1
> y b2
> z c3
> b x d4
> y e5
> z f6
> CHARIZARD
> CHARIZARD
> a ^x
> y
> z
> e ^x
> x
> d qwerty ^x azerty aBc
>
>
> Also, it matches incorrectly.
>
> * An extra CHARIZARD line was inserted
> * "x " at the beginning of the penultimate line was NOT matched
>
> My intended result is to ADD text to the end of any lines that start
> with "x ".
>
>
> c ^x a1
> y b2
> z c3
> b x d4
> y e5
> z f6
> x abC W-CHARIZARD
> a ^x
> y
> z
> e ^x
> x CHARIZARD
> d qwerty ^x azerty aBc
>
I don't remember what it did, but I tried -n, and it gave a worse
result.
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